ln(2x^2)+ln(3x)=4

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Solution for ln(2x^2)+ln(3x)=4 equation:


Simplifying
ln(2x2) + ln(3x) = 4

Remove parenthesis around (2x2)
ln * 2x2 + ln(3x) = 4

Reorder the terms for easier multiplication:
2ln * x2 + ln(3x) = 4

Multiply ln * x2
2lnx2 + ln(3x) = 4

Remove parenthesis around (3x)
2lnx2 + ln * 3x = 4

Reorder the terms for easier multiplication:
2lnx2 + 3ln * x = 4

Multiply ln * x
2lnx2 + 3lnx = 4

Reorder the terms:
3lnx + 2lnx2 = 4

Solving
3lnx + 2lnx2 = 4

Solving for variable 'l'.

Move all terms containing l to the left, all other terms to the right.

Reorder the terms:
-4 + 3lnx + 2lnx2 = 4 + -4

Combine like terms: 4 + -4 = 0
-4 + 3lnx + 2lnx2 = 0

The solution to this equation could not be determined.

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